Question

A ball is thrown into the air with an initial velocity of 15 m/s, how high into the air does the ball travel?

Answer 1

Answer:

11.25m

Explanation:

vf^2=vi^2+2ad

0^2=15^2+2×(-10)d

0=225+-20d(remove 225 by doing the opposite operation)

-225÷-20=-20d÷-20(remove -20 by dividing by itself)

11.25= d (the answer becomes this)