Answer: [tex]h = \frac{125a}{3}[/tex]
Step-by-step explanation:
Volume of sphere = [tex]\frac{4}{3}\pi r^{3}[/tex]
radius = [tex]5a[/tex]
Volume of cylinder = [tex]\pi r^{2}h[/tex]
radius = [tex]2a[/tex]
substituting the radius given and equating the two , we have :
[tex]\frac{4}{3}\pi (5a)^{3} = \pi (a)^{2}h[/tex]
[tex]\pi[/tex] is common to the two , this means that it cancels out , the equation then becomes :
[tex]\frac{4}{3}(125a^{3}) = 4a^{2}h[/tex]
[tex]a^{2}[/tex] is also common , then we have
[tex]\frac{4}{3}(125a) = 4h[/tex]
multiply through by 3
[tex]4(125a) = 12h[/tex]
divide through by 4
[tex]125a = 3h[/tex]
divide through by 3
[tex]h = \frac{125a}{3}[/tex]