Question

A ball is dropped from the top of a cliff 651 m high. How long does it take the ball to hit the ground at the bottom of the cliff, in seconds?

Answer 1

Answer:

t = 11.41 seconds

Explanation:

h = 1/2 gt^2

h = height

g = acceleration due to gravity

t = time

651 = 1/2 x 10 x t^2

651 = 5 x t^2

t^2 = 651/ 5

t^2 = 130.2

t = square root of 130.2

t = 11.41 seconds