Question

A person walks 25.0° North of East for 3.10 km. How far would she have to walk due north and due east to arrive at the same location?

Answer 1

Northward = R sin 25° =  3.10 sin(25) = 1.31 km

Eastward =   R cos 25° = 3.10. cos (25) =           2.81 km

Explanation:

actually in this question , you have to find out the components of a vector 25° North of east with a magnitude of 3.10 km.

Northward = R sin 25° =  3.10 sin(25) = 1.31 km

Eastward =   R cos 25° = 3.10. cos (25) = 2.81 km