Question

4x2 + y2 = 36
Obtener dominio

Answer 1

Answer:

[-3,3]

Step-by-step explanation:

Write the problem as a mathematical expression.

4x^2+y^2=36

Subtract 4x^2 from both sides of the equation.

y^2=36-4x^2

Take the square root of both sides of the equation to eliminate the exponent on the left side.

y= + and - $\sqrt{36-4x^2}$

The complete solution is the result of both the positive and negative portions of the solution.

y= $2\sqrt{(3+x)(3-x)$

$y= -2\sqrt{(3+x)(3-x)}$

Set the radicand in $\sqrt{(3+x)(3-x)} \geq 0$ greater than or equal to 0 to find where the expression is defined.

$(3+x)(3-x)\geq 0$

So your answer would be [-3,3]