Answer:
It is the main heat loss mechanism at rest.
Explanation:
A man of surface area 1.8 m2 and body temperature 34 ∘C was determined to lose energy to a 25 ∘C room at the rate of 88 Kcal/hr. Compare this to the basal metabolic rate of a 65 kg man using Kleiber's Law. What does this suggest about radiative heat loss?
kleiber's law identified that the metabolic rate of an animal is equal to three-fourth of its power.
The energy radiated by the body and the energy absorbed from surrounding is given by:
Hr = Kr Ar e ( Ts - Tw )
from the above formula
Hr = energy loss or gain
Ar = surface area emitting radiation
E = emissivity of body
Ts = skin temperature
Tw =surrounding temp.
Kr = constant = 5 Kcal / m2 hr Cº
this suggest to us that radioactive heat loss is the main heat loss mechanism at rest.
