Question

What is the proportion of scores in a normal distribution between the mean (z = 0.00) and z = +0.52?

Answer 1

Answer:

20%

Step-by-step explanation:

We are asked to find the proportion of of scores in a normal distribution between the mean (z = 0.00) and z = +0.52.

We will use normal distribution table to find area under normal distribution curve corresponding to given score as:

$P(0.00<z<0.52)=P(z<0.52)-P(z<0.00)$

Using normal distribution table, we will get:

$P(0.00<z<0.52)=0.69847 -0.50000$

$P(0.00<z<0.52)=0.19847$

$P(0.00<z<0.52)=19.847\%$

$P(0.00<z<0.52)\approx 20\%$

Therefore, approximately 20% of scores in a normal distribution between the given z-scores.