Which statement is FALSE? ► View Available Hint(s)

a. One mole of beryllium (Be) contains the same number of atoms as 22.99 g of sodium.

b. One mole of calcium (Ca) weighs about as much as two moles of neon (Ne). 11.495 g of sodium contains 6.022 x 1023 atoms.

c. There are about 2.007 x 1023 atoms in 9.0 g Al

Respuesta :

Answer:

The correct answer is: B

Explanation:

The false statement here is, 11.495 g of sodium contains 6.022 x 10^23 atoms.

a) For the first statement, the molar mass of Na is 23 g/mol

Number of moles in 22.99 g of sodium = 22.99 g/23 g/mol = 0.9996 moles

If 1 mole of Na contains 6.02 × 10^23 atoms

0.9996 moles of Na contains 0.9996 moles × 6.02 × 10^23 atoms/ 1 mole

= 6.02 × 10^23 atoms.

Since 1 mole of Be contains  6.02 × 10^23 atoms, the statement is True.

b) One mole of calcium atom is about 40 g/mol while one mole of Ne is about 20 g/mol hence one mole of calcium (Ca) weighs about as much as two moles of neon (Ne) hence the statement is true.

c) Molar mass of Na = 23 g/mol

Number of moles in 11.495 g of sodium = 11.495 g/23 g/mol = 0.4998 moles

1 mole of Na contains  6.022 x 10^23 atoms

0.4998 moles of Na contains 0.4998 moles x 6.022 x 10^23 atoms/1 mole

= 3.00 x 10^23 atoms hence the statement is false.

d) Molar mass of Al = 27 g/mol

Number of moles in 9.0 g Al = 9.0 g/27 g/mol = 0.33 moles of Al

If 1 mole of Al contains 6.022 x 10^23 atoms

0.33 moles of Al contains 0.33 moles x 6.022 x 10^23 atoms/1 mole

= 2 x 10^23 atoms.

Hence, the statement is true.

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