Respuesta :
Answer:
The maximum possible amount that could be awarded under the two-deviation rule is $ 1.883 Million.
Step-by-step explanation:
In order to find the maximum possible amount of the award, the formula is given as
[tex]x=\bar{x}+2s[/tex]
Here
[tex]\bar{x}[/tex] is the mean of the samples and is given as
[tex]\bar{x}= \frac{\sum_{i=1}^{n} x_i}{n}[/tex]
s is the standard deviation which is given as
[tex]s=\sqrt{\frac{1}{n-1} (\sum x_i^2-\frac{1}{n} (\sum x_i)^2 )}[/tex]
Putting values as
[tex]\sum x_i^2=23,465,528 \$ (1000s) \\ \sum x_i=20,180 \$ (1000s) \\ n=27[/tex]
Substituting the values in the equation of mean is as
[tex]\bar{x}= \frac{20,180}{27} \\ \bar{x}= 747.407 \$ (1000s)[/tex]
Where as standard deviation is given as
[tex]s=\sqrt{\frac{1}{27-1} (23,465,528-\frac{1}{27} (20,180)^2 )} \\ s=\sqrt{\frac{1}{26} (23,465,528-15082681.4815 )} \\s=\sqrt{\frac{1}{26} (8382846.51)} \\s=\sqrt{322417.17} \\s=567.81 \$ (1000s)[/tex]
Putting this in the equation of maximum amount gives
[tex]x=\bar{x}+2.s \\ x=747.407 +2(567.81) \\x=1883.04 \$ (1000s)[/tex]
So the maximum possible amount that can be awarded in this case is 1883.04 thousand dollars or $ 1.883 Million. This value is less than the previously maximum value which is $3.5 million.