Respuesta :
Answer:
Option b. LaToyna and Ming, LaToyna and Jose, LaToyna and John, LaToyna and Prof. Rise, LaToyna and Dr. Hernandez, Ming and Jose, Ming and John, Ming and Prof. Rise, Ming and Dr. Hernandez, Jose and John, Jose and Dr. Hernandez, John and Prof. rise, John and Dr. Hernandez, Prof rise and Dr Hernandez.
Step-by-step explanation:
In the question it is stated that we have to form a subcommittee of two members from the given 6 members, for this we have to list all possible simple random samples of size of 2 members.
For this we know that there would be 14 groups of 2 members each because:
LaToyna will combine with Ming, Jose, John, Prof. Rise, and Dr. Hernandez; so there will be 5 groups for LaToyna.
Ming will combine with Jose, John, Prof. Rise, and Dr. Hernandez ; so there will be 4 groups for Ming because his group with LaToyna is included above.
Jose will combine with Prof. Rise, and Dr. Hernandez ; so there will be 2 groups for Jose.
John will combine with Prof. Rise, and Dr. Hernandez ; so there will be 2 groups for John.
Prof. Rise will combine with Dr. Hernandez ; so there will be 1 group for Prof. Rise as he is included with other members in the above groups.
So total groups will be = 5+4+2+2+1 = 14 groups.
Therefore, option b is correct.
