Respuesta :
Answer:
The complete part of the question is ; In the circuit in the figure, (Figure 1)a 20-ohm resistor sits inside 110 g of pure water that is surrounded by insulating Styrofoam. If the water is initially at temperature 10.2 ∘C, how long will it take for its temperature to rise to 57.9 ∘C?
Use 4190J/kg⋅C∘ as the heat capacity of water, and express your answer in seconds using three significant figures.
answer = time taken = 1099.24secs
Explanation:
Tthe detailed calculation is as shown in the attachment.
The principle applied is the resolution of resistance of circuit in series and in parralel and then finding the equivlaent resistance.
Use the ohm's law equation to find the current in the circuit.
Use the Power generated
From the specific heat capacity equation to get the time duration.
The resistors in the circuit with the equivalent resistance generates power and specific heat, adds the calculation of time for the change in temperature. The time required for the water is 676.5528 seconds.
What is specific heat?
The specific heat is the amount of heat added to raise the temperature of 1 gram of substance by 1 degree Celsius.
The circuit has the presence of equivalent resistance from the series and parallel circuit is 30 ohms.
The voltage of the circuit is 30 V. The current is given as :
[tex]\rm I=\dfrac{V}{R}\\ I=\dfrac{30\;V}{30\;\Omega} \\I=1\;A[/tex]
The power ([tex]P[/tex]) generated by the circuit is given as:
[tex]P=IR\\P=1\;\times\;30\\P=30[/tex]
The heat generated ([tex]Q[/tex]) has been,
[tex]Q=Pt\\Q=30t[/tex]
The specific heat of water is given as:
[tex]Q=mc\Delta T[/tex]
Substituting the value of Q, mass, specific heat, and change in temperature:
[tex]30t=110\;\text g\;\times\;4.184\;\text J\;\times\;(57.9-102^\circ\;\text C)\\t=676.5528\;\rm sec[/tex]
The time required by water to change the temperature is 676.5528 seconds.
Learn more about specific heat, here:
https://brainly.com/question/2516072
