Answer:
a)F=(208 i+156 j) kN
b)F+W=219 kN
Explanation:
Solution:
To determine the components of F
F=(260 kN).([tex]\frac{4}{\sqrt{4^{2}+3^{2}}}i+\frac{3}{\sqrt{4^{2}+3^{2}}}j[/tex])
=(208 i+156 j) kN
F=(208 i+156 j) kN
b)weight W expressed in component and add into the
Force F.
W=-(8800 kg).(9.81 m/s^2)j
F+W=(208 i+[156-86.3]j) kN
F+W=[tex]\sqrt{(208kN)^{2}+(-69.7kN)^{2} }[/tex]
=219 kN
F+W=219 kN