Answer:
(B) False, because if the [tex]H_{0}[/tex] holds, then p in the sample will be greater than or equal to 0.40.
Step-by-step explanation:
The analysis of the costs and benefits of adding this service shows that the it will be profitable if 40% or more of the firm's customer uses it.
Now to test this result the firm needs to survey its customers.
The hypothesis will be defined as:
[tex]H_{0}:[/tex] The proportion of customers using the service is 40% or more, i.e [tex]p\geq 0.40[/tex]
[tex]H_{1}:[/tex] The proportion of customers using the service is less than 40%, i.e [tex]p< 0.40[/tex]
Let X = number of customers who will use the service.
Then X will follow a Binomial distribution.
Using the Normal approximation we can approximate the binomial distribution by the normal distribution.
The test statistic used is:
[tex]z=\frac{\hat p-p}{\sqrt\frac{p(1-p)}{n} }[/tex]
If the null hypothesis ([tex]H_{0}[/tex]) is true, this implies that the test statistic is in the acceptance region. For this to happen the sample proportion ([tex]\hat p[/tex]) must be greater than the 0.40.
And as the test is left tailed the critical value will be negative.
So, with the test statistic is in the acceptance region and a negative critical value it will imply that the sample proportion is more than or equal to p = 0.40.
Thus, the correct option is (B).