Respuesta :
Answer:
[tex]r=\frac{10(6811)-(92)(723)}{\sqrt{[10(878) -(92)^2][10(53395) -(723)^2]}}=0.8465[/tex]
So then the correlation coefficient would be r =0.8465
And the best options would be:
(D) 0.847
Step-by-step explanation:
Previous concepts
The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.
And in order to calculate the correlation coefficient we can use this formula:
[tex]r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}[/tex]
Solution to the problem
Data given:
X: 8 10 7 13 7 9 9 10 11 8
Y: 60 75 55 83 61 73 80 85 85 66
For our case we have this:
n=10 [tex] \sum x = 92, \sum y = 723, \sum xy = 6811, \sum x^2 =878, \sum y^2 =53395[/tex]
And if we replace into the formula we got:
[tex]r=\frac{10(6811)-(92)(723)}{\sqrt{[10(878) -(92)^2][10(53395) -(723)^2]}}=0.8465[/tex]
So then the correlation coefficient would be r =0.8465
And the best options would be:
(D) 0.847
The correlation coefficient is (D) 0.847
Correlation coefficients are used to measure how strong a relationship is between two variables. It's denoted by r and its always between -1 and 1.
We know the correlation coefficient formula is:
[tex]r=\frac{\sum xy-\sum x.\sum y}{n\sum x^{2} -\sum(x)^{2}-n\sum y^{2} -\sum(y)^{2}}[/tex]
We have given data:
Hours X: 8 10 7 13 7 9 9 10 11 8
Scores Y: 60 75 55 83 61 73 80 85 85 66
In this case we have:
n=10
And [tex]\sum x=92,\sum y=723,\sum xy=6811,\sum x^{2} =878, \sum y^{2} =53395[/tex]
Substituting the values in the co relation formula, we get
[tex]r=\frac{10(6811)-92(723)}{[10(878)-92^{2}][10(5335)-723^{2} } \\r=0.847[/tex]
Therefore, the correlation coefficient is r =0.8465
So, the correct option is (D).
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