Question

What is y + 11 = 1/3(x + 3) in standard form?

Answer 1

Standard form is y=Mx+b so first step is to isolate y:
Y=1/3(x+3)-11

Then use order of operations to simplify the x to a whole number. First multiply by three:
3y=x+3-33

Now combine like terms:
3y=x-30

Finally,
Divide to make y have a coefficient if one:

Y= 1/3x -10

Answer 2

The standard form is "$\bold{y=\frac{x}{3}-10}$".

Standard form:

$\to y + 11 =\frac{1}{3}(x + 3)$

standard form=?

The formula for standard form:

$\to y= mx+c$

Solving the given expression:

$\to y + 11 =\frac{1}{3}(x + 3)\\\\\to y + 11 =\frac{x}{3} + \frac{3}{3}\\\\\to y + 11 =\frac{x}{3} +1\\\\\to y =\frac{x}{3} +1-11\\\\\to y =\frac{x}{3} -10$

Therefore the standard form is "$\bold{y=\frac{x}{3}-10}$".

Learn more about the standard form here:

brainly.com/question/8048237