Answer:
a) t = 4/3 s = 1.33 s
b) ∆x = -9.0 m
c) Velocity v = -3m/s
Explanation:
Given;
The position function of the particle can be represented by;
x(t) = 4.0 - 3.0t m
a) the time that the particle cross the origin, at this time x(t) = 0 (origin). So;
x(t) = 4.0 - 3.0t = 0
4.0 - 3.0t = 0
3.0t = 4.0
t = 4/3 s = 1.33 s
b) change in displacement between t = 3s and t = 6s
At t = 3s
x(3) = 4 - 3(3) = -5 m
At t = 6s
x(6) = 4 - 3(6) = -14m
∆x = x(6) - x(3) = -14 - (-5) = -14+5 = -9m
∆x = -9.0 m
c) velocity is the change in displacement per unit time.
x(2) = 4 - 3(2) = -2
x(4) = 4 - 3(4) = -8
∆x = -8 - (-2) = -6 m
∆t = 4 - 2 = 2 s
v = ∆x/∆t = -6/2 = -3 m/s
Velocity v = -3m/s
