Answer: 2 half lives have passed.
Explanation:
The formula used is;
[tex]a=\frac{a_o}{2^n}[/tex]
where,
a = amount of reactant left after n-half lives = 250 atoms
[tex]a_o[/tex] = Initial amount of the reactant = 1000 atoms
n = number of half lives= ?
Putting values in above equation, we get:
[tex]250=\frac{1000}{2^n}[/tex]
[tex]2^n=4[/tex]
[tex]2^n=2^2[/tex]
[tex]n=2[/tex]
Therefore, 2 half lives have passed.