Question

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Find the first three terms of the sequence below.
In = 3n2 – 4n - 3
T1=?
T2 =?
T3=?
please help me i’m stuck

Answer 1

$T_1 = -3\\T_2=-4\\T_3=1$

Step-by-step explanation:

Given sequence is $3n^2-4n -3$

$T_1$ $=3(0)^2-4.0 -3$  $= -3$     [putting n=0 in given sequence]

$T_2$$= 3(1)^2 -4.1-3$ $= -4$       [putting n=1 in given sequence]

$T_3=3(2)^2 - 4.2-3$ $= 1$         [putting n=2 in given sequence]