Answer:
a = 4.59 m/s²
Explanation:
given,
initial speed of the car = 0 m/s
final speed of the car = 145 km/h
1 Km/h = 0.278 m/s
145 Km/h = 145 x 0.278 = 40.31 m/s
time, t = 8.78 m/s
Acceleration of car before collision
[tex]a = \dfrac{\Delta v}{t}[/tex]
[tex]a = \dfrac{v_f- v_i}{t}[/tex]
[tex]a = \dfrac{40.31 - 0 }{8.78}[/tex]
a = 4.59 m/s²
The magnitude of acceleration before collision is 4.59 m/s²