Question

Palladium forms 3 different compounds with sulfur. The mass of sulfur per gram of palladium in each compound is listed below.

Compound Grams S per gram Pd

A 0.603

B 0.301

C 0.151

Show that these masses are consistent with the law of multiple proportions.

Answer 1

Explanation:

Compound A:

Mass of sulphur = 0.603g

Mass of Palladium = 0.397g

0.603g of sulphur combine with 0.397g of Palladium.

Therefore, 1g of sulphur will combine with = 0.397 / 0.603 = 0.658g of Palladium

Compound B:

Mass of sulphur = 0.301g

Mass of Palladium = 0.699

0.301g of sulphur combine with 0.699g of Palladium. Therefore, 1g of sulphur will combine with

= 0.699 / 0.301 = 2.322g of Palladium

Compound C:

Mass of sulphur = 0.151g

Mass of Palladium = 0.849g

0. 151g of sulphur combine with 0.849g of Palladium,

Therefore 1g of sulphur will combine with = 0.849/ 0.151 = 5.623g of Palladium

Therefore, the masses of Palladium which combine with a mixed mass (1g) of sulphur are in ratio

0.658 : 2.322 : 5.623 i.e 1: 4 : 9 which is a simple ratio