Respuesta :
Answer: The possible charges of the oil droplets are [tex]-3.2\times 10^{-19}C[/tex] , [tex]-4.8\times 10^{-19}C[/tex] and [tex]-8.0\times 10^{-19}C[/tex]
Explanation:
Millikan’s oil drop experiment is used to measure the charge of an electron. Before this experiment, the subatomic particles were not accepted.
The charge on the oil drop was calculated using the equation:
[tex]Q=\frac{m\cdot g}{E}[/tex]
He found that all the oil drops had charges that were the multiples of [tex]-1.6\times 10^{-19}C[/tex]. This value is the charge on 1 electron
Number of electrons excess electrons is calculated by using the formula:
[tex]\text{Excess electrons}=\frac{\text{Charge on millikan's oil drop}}{\text{Charge on 1 electron}}[/tex]
From the given options:
- Option A: [tex]-1.2\times 10^{-19}C[/tex]
[tex]\text{Excess electrons}=\frac{-1.2\times 10^{-19}}{-1.6\times 10^{-19}}=0.75[/tex]
This cannot be taken as the charge on an oil drop.
- Option B: [tex]-3.2\times 10^{-19}C[/tex]
[tex]\text{Excess electrons}=\frac{-3.2\times 10^{-19}}{-1.6\times 10^{-19}}=2[/tex]
This can be taken as the charge on an oil drop.
- Option C: [tex]-4.8\times 10^{-19}C[/tex]
[tex]\text{Excess electrons}=\frac{-4.8\times 10^{-19}}{-1.6\times 10^{-19}}=3[/tex]
This can be taken as the charge on an oil drop.
- Option D: [tex]-5.6\times 10^{-19}C[/tex]
[tex]\text{Excess electrons}=\frac{-5.6\times 10^{-19}}{-1.6\times 10^{-19}}=3.5[/tex]
This cannot be taken as the charge on an oil drop.
- Option E: [tex]-8.0\times 10^{-19}C[/tex]
[tex]\text{Excess electrons}=\frac{-8.0\times 10^{-19}}{-1.6\times 10^{-19}}=5[/tex]
This can be taken as the charge on an oil drop.
- Option F: [tex]-9.4\times 10^{-19}C[/tex]
[tex]\text{Excess electrons}=\frac{-1.2\times 10^{-19}}{-1.6\times 10^{-19}}=5.875[/tex]
This cannot be taken as the charge on an oil drop.
Hence, the possible charges of the oil droplets are [tex]-3.2\times 10^{-19}C[/tex] , [tex]-4.8\times 10^{-19}C[/tex] and [tex]-8.0\times 10^{-19}C[/tex]
