Answer:
[tex]15x\leq 125[/tex]
8 calculators at most.
Step-by-step explanation:
Let x represent number of calculators.
We have been given that each calculator costs $15. So the cost of x calculators would be [tex]15x[/tex] dollars.
Since the order must be less than $125 in order to not go over budget, so cost of x calculators should be less than or equal to 125. We can represent this information in an inequality as:
[tex]15x\leq 125[/tex]
Therefore, our required inequality would be [tex]15x\leq 125[/tex].
Let us divide both sides of inequality by 15 as:
[tex]\frac{15x}{15}\leq \frac{125}{15}[/tex]
[tex]x\leq8.3333[/tex]
Since we cannot order 0.33 of a calculator, therefore, the math club can order 8 calculators at most.