Question

Calculate the concentration of an aqueous solution of Ca(OH)2 that has a pH of 12.01. Express your answer using two significant figures.

Answer 1

Answer:

The concentration of Ca(OH)₂ aqueous solution of pH 12.01 is 0.0051 M

Explanation:

Because in water, the selft ionization constant of water is  [H⁺][OH⁻] = 10⁻¹⁴ or pH + pOH = 14

Given pH = 12.01, so pOH = 14 - 12.01 = 1.99

The concentration of OH⁻ is 10^(1.99) = 0.010 M

The equation is: Ca(OH)₂ → Ca²⁺ + 2 OH⁻

So the concentration of Ca(OH)₂ (aq) is 0.010 / 2 = 0.0050 M

Answer 2

The concentration for the aqueous solution of pH is 0.0051 M

What is the method of finding the concertation of aqueous solution ?

As the aqueous solution of Ca(OH)2 consists of the pH of about 12.01. The ionization constant of water is  the [H⁺] [OH⁻] =  10⁻¹⁴ or pH + pOH = 14

Thus , given pH equal to  12.01, so pOH = 14 - 12.01 = 1.99 The concentration of the OH⁻ is 10^(1.99) = 0.010 M.  As per the equation of is: Ca(OH)₂ → Ca²⁺ + 2 OH⁻

Hence the type of concertation of the  Ca(OH)₂ (aq) is 0.010 / 2 = 0.0050 M.

Find out more information about the aqueous solution.

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