Question

what is the 5th term in the sequence d(n)=5/16 (2)^n−1

Answer 1

Step-by-step explanation:

Hope that given sequence is written like as given below. If it is so, then let us find:

$\: \: \: \: \: \: d(n) = \frac{5}{16} \times {2}^{n - 1} \\ \therefore \: d(5) = \frac{5}{16} \times {2}^{5 - 1} \\ \therefore \: d(5) = \frac{5}{16} \times {2}^{4} \\ \therefore \: d(5) = \frac{5}{16} \times 16\\ \therefore \: d(5) = 5 \times 1 \\ \\ \huge \orange{ \boxed{ \therefore \: d(5) = 5 }}$

Thus, 5th term of given sequence is 5.