Question

Glucose, C6H12O6, is a good source of food energy. When it reacts with oxygen, carbon dioxide and water are formed. How many liters of CO2 are produced when 126 g of glucose completely react with oxygen?

Answer 1

Answer: The volume of carbon dioxide gas produced is 95.96 L

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of glucose = 126 g

Molar mass of glucose = 180.2 g/mol

Putting values in above equation, we get:

$\text{Moles of glucose}=\frac{126g}{180.2g/mol}=0.699mol$

The chemical equation for the combustion of glucose follows:

$C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O$

By Stoichiometry of the reaction:

1 mole of glucose reacts with 6 moles of carbon dioxide gas

So, 0.699 moles of glucose will produce = $\frac{6}{1}\times 0.699=4.194mol$ of carbon dioxide gas

At STP:

1 mole of a gas occupies 22.4 L of volume

So, 4.194 moles of carbon dioxide gas will occupy $\frac{22.4}{1}\times 4.194=95.96L$ of volume

Hence, the volume of carbon dioxide gas produced is 95.96 L