Question

HELP PLEASE!
What is the x-coordinate of one solution to the following system?

y=6x^2+12x+2

y=4x^2+16x+16

a. -1.83

b. -11.31

c. 1.00

d. 13.67

Answer 1

Answer:

a

Step-by-step explanation:

y=6x²+12x+2

y=4x²+16x+16

6x²+12x+2=4x²+16x+16

6x²-4x²+12x-16x+2-16=0

2x²-4x-14=0

x²-2x-7=0

x²-2x+1-1-7=0

(x-1)²=8

x-1=±√8=±2√2

x=1±2√2

x≈1±2.83

x≈3.83,-1.83

x=2√2 -1≈1.828≈1.83