Respuesta :
Answer:
The solution to the given functions f(x) and g(x) is 1
Therefore f(x)=g(x)=0 when x=1
Step-by-step explanation:
Given that the functions f(x) and g(x) defined as below
[tex]f(x)=\frac{-11x}{3}+\frac{11}{3}[/tex]
and [tex]g(x)=x^3+2x^2-x-2[/tex]
To verify that the solution satisfies f(x)=g(x) :
Put x=1 in f(x) and g(x) we get
[tex]f(x)=\frac{-11(1)}{3}+\frac{11}{3}[/tex]
[tex]=-\frac{11}{3}+\frac{11}{3}[/tex]
[tex]=0[/tex]
Therefore f(x)=0 when x=1
put x=1 [tex]g(1)=1^3+2(1)^2-1-2[/tex]
[tex]=1+2-1-2[/tex]
[tex]=0[/tex]
Therefore g(x)=0 when x=1
Therefore f(x)=g(x)=0 when x=1
Therefore the solution to the given functions f(x) and g(x) is 1.
Answer: x = 1
Step-by-step explanation:
The solution is simply the point where the two lines intersect on the graph. In this problem, the two lines cross each other at 1, so that would be the solution.