Answer:
[tex] \bar X -2s = 27.12- (2*1.13) =24.86[/tex]
[tex] \bar X +2s = 27.12+(2*1.13) =29.38[/tex]
So if a value is less than 24.86 would be considered significantly low and a value higher than 29.38 would be considered as significantly high.
The value for the analysis is 29.8 and as we can see 29.8>29.38 so then we can consider 29.8 as a value significantly high.
Step-by-step explanation:
For this case we have the mean given [tex] \bar X = 27.12 [/tex] and the deviation [tex] s= 1.13[/tex]
The Range Rule of Thumb says "that the range is about four times the standard deviation"
So then we will ave approximately most of the value within 2 deviations from the mean, so we can find the limits considered normally like this:
[tex] \bar X -2s = 27.12- (2*1.13) =24.86[/tex]
[tex] \bar X +2s = 27.12+(2*1.13) =29.38[/tex]
So if a value is less than 24.86 would be considered significantly low and a value higher than 29.38 would be considered as significantly high.
The value for the analysis is 29.8 and as we can see 29.8>29.38 so then we can consider 29.8 as a value significantly high.