Question

$\frac{3}{4}n-18=\frac{1}{4} n-4$

Answer 1

The value of n is $n=28$

Explanation:

The expression is $\frac{3}{4} n-18=\frac{1}{4} n-4$

Subtracting both sides by $\frac{1}{4} n$, we get,

$\frac{3}{4}n-\frac{1}{4}n-18=-4$

Adding both sides by 18, we get,

$\frac{3}{4}n-\frac{1}{4}n=-4+18$

Simplifying the terms, we have,

$\frac{2}{4}n=14$

Dividing, we get,

$\frac{1}{2} n=14$

Multiplying by 2, we have,

$n=28$

Thus, the value of n is $n=28$