Answer:
Step-by-step explanation:
Given that A be the event that a randomly selected voter has a favorable view of a certain party’s senatorial candidate, and let B be the corresponding event for that party’s gubernatorial candidate.
Suppose that
P(A′) = .44, P(B′) = .57, and P(A ⋃ B) = .68
From the above we can find out
P(A) = [tex]1-0.44 = 0.56[/tex]
P(B) = [tex]1-0.57 = 0.43[/tex]
P(AUB) = 0.68 =
[tex]0.56+0.43-P(A\bigcap B)\\P(A\bigcap B)=0.30[/tex]
a) the probability that a randomly selected voter has a favorable view of both candidates=P(AB) = 0.30
b) the probability that a randomly selected voter has a favorable view of exactly one of these candidates
= P(A)-P(AB)+P(B)-P(AB)
[tex]=0.99-0.30-0.30\\=0.39[/tex]
c) the probability that a randomly selected voter has an unfavorable view of at least one of these candidates
=P(A'UB') = P(AB)'
=[tex]1-0.30\\=0.70[/tex]