A sealed rectangular container 10 inches by 12 inches by 6 inches is sitting on its largest face. If it is filled with water up to a level 2 inches from the top, how many inches from the bottom will the water level reach if the container is placed on its smallest face?

Respuesta :

Answer:

8 inches

Step-by-step explanation:

Given: Dimension of rectangular container= [tex](10\times12\times 6)\ inches[/tex]

           Water is filled up to a level 2 inches from the top.

As given that container is sitting on its largest face, then it is standing on [tex](10\times 12)\ inches[/tex]

Which means the height of container is 6 inches and it ie filled with water up to 2 inches from the top.

∴ Height of water inside the container= [tex]6-2= 4 \ inches[/tex]

Now, finding the volume of water inside.

we know, Volume= [tex]length\times width\times height[/tex]

Volume= [tex]10\times 12\times 4= 480\ inches^{3}[/tex]

Next, if container is placed in its smallest face then it is standing on [tex](10\times 6)\ inches[/tex] and lets assume height to be "x"

Forming an equation now to express the volume conservation law.

⇒ [tex]480\ inches^{3} = 10\times 6\times x[/tex]

⇒[tex]480= 60x[/tex]

dividing both side by 60

⇒[tex]x= \frac{480}{60}[/tex]

x= 8 inches

Hence, 8 inches from the bottom will the water level reach if the container is placed on its smallest face

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