Answer: 16.34g/mol
Explanation:
V = 250 cm³ = 0.25L
T = 298 K
R = 0.082atm.L.K^-1.mol^-1
P = 152 Torr = (152/760)atm = 0.2atm
mass of the gas = 33.5 mg = 0.0335g
n =?
PV = nRT
n = PV / RT = (0.2x0.25)/(0.082x298)
n = 0.00205mol
n = Mass / Molar Mass
Molar Mass = Mass / n = 0.0335/0.00205 = 16.34 g/mol