Respuesta :

Answer:

x  = -1 is one solution of the equation.

Another solution is x [tex]\approx[/tex] 3.13

Step-by-step explanation:

i) let the require number be x

ii) therefore from the problem we can write the equation

[tex]\frac{16}{x-3} = 4x^{3}[/tex]

Therefore [tex]4x^4 - 12x^3 - 16 = 0[/tex]

On inspection we can see that x  = -1 is one solution of the equation.

Another solution is x [tex]\approx[/tex] 3.13

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