Answer:
x = -1 is one solution of the equation.
Another solution is x [tex]\approx[/tex] 3.13
Step-by-step explanation:
i) let the require number be x
ii) therefore from the problem we can write the equation
[tex]\frac{16}{x-3} = 4x^{3}[/tex]
Therefore [tex]4x^4 - 12x^3 - 16 = 0[/tex]
On inspection we can see that x = -1 is one solution of the equation.
Another solution is x [tex]\approx[/tex] 3.13
