Question

Determine the energy required to accelerate a 1270-kg car from 10 to 60 km/h on an uphill road with a vertical rise of 40 m. (Round the final answer to the nearest whole number.) The energy required to accelerate the car uphill is kJ.

Answer 1

Answer:

E= 679.83 KJ

Explanation:

Given that

m = 1270 kg

u = 10 km/h

We know that 1 km/h = 0.27 m/s

u = 2.7 m/s

v= 16.67 m/s

h = 40 m

By using energy conservation

The energy required =E

$E=\dfrac{1}{2}m (v^2-u^2)+mgh$

Now by putting the values in the above equation

$E=\dfrac{1}{2}\times 1270\times (16.67^2-2.7^2)+1270\times 10\times 40$

We are taking g= 10 m/s²

Now by solving above equation we get

E= 679830.30 J

E= 679.83 KJ

The energy required will be 679.83 KJ