Question

c. How many grams of Na2SiO3 can react with 0.800 g of HF?

Answer 1

Answer:

Mass = 0.610 g

Explanation:

Given data:

Mass of Na₂SiO₃ = ?

Mass of HF = 0.800 g

Solution:

Chemical equation:

Na₂SiO₃ + 8HF   →    H₂SiF₆ + 2NaF + 3H₂O

Number of moles of HF:

Number of moles = mass/ molar mass

Number of moles = 0.800 g/ 20 g/mol

Number of moles = 0.04 mol

Now we will compare the moles of HF and Na₂SiO₃.

           HF        :        Na₂SiO₃

            8          :          1

            0.04    :       1//8×0.04 = 0.005

Mass of Na₂SiO₃:

Mass = number of moles × molar mass

Mass =   0.005 mol  × 122.07 g/mol  

Mass = 0.610 g