Question

Analyze the following code segment:
#include
void xFunction(int * n);
int main()
{
int n=5;
xFunction(&n);
printf("%d",n);
} void xFunction(int* n)
{
*n= *n +70;
*n=90;
}

Answer 1

Answer:

90 is the output for the above program segment.

Explanation:

• 90 will be the value for the n variable. It is because the "xfunction()" takes the address of the n variable as an argument.
• Then the "xfunction()" changes the value of the address of n variable.
• It is because the address of the n variable is addressed by the n pointer variable of integer type in "xfunction()".
• And, then the first statement of the "xfunction()" changes the value to be 75 of n variable by the help of its address.
• And then the second statement of the "xfunction()" assigns the value 90 to the address position of n variable.
• And hence the output will be 90 when the user prints the value of n variable.