Respuesta :
Answer:
The answer is b), -228 kJ
Explanation:
First, we consider which bonds are broken and formed during the reaction
Broken, Br - Br (02 molecules), C ≡ C
Formed, C - C, C - Br (4 bonds)
Noted that when breaking bonds, the molecules NEED energy, while forming bond, they release energy. So, secondly, we calculate
Breaking energy = 2 x (Br-Br) + 1 x (C≡C) = 2 x 193 + 1 x 837 = 1,223 kJ
Forming energy = - (4 x (C-Br) + 1 x (C-C) = - (4 x 276 + 1 x 347) = - 1,451 kJ (minus means that the energy is released during the reaction)
Hence the ΔH°ᵣₓₙ is 1,223 kJ + (-1,451) kJ = - 228 kJ
Answer:
So energy released in the given reaction is -228 kJ/mol
Explanation:
[tex]\rm \Delta H^0_r_x[/tex] of the reaction is the net energy of the reaction. For considering the net energy of the reaction, the account of all the bonds broken and formed is considered.
In the above reaction, there is:
Broken bonds - 2 Br-Br bonds
1 C [tex]\equiv[/tex] C bond
Bonds formed = 1 C-C bond
4 C-Br bonds
The formation of bonds requires energy while breaking of bond releases energy.
From the given energies, total energy used in the breaking of bonds is:
Br-Br bonds = 2 * 193 kJ/mol
= 386 kJ/mol
C [tex]\equiv[/tex] C bond = 837 kJ/mol
Total energy for breaking of bond = 386 kJ/mol + 837 kJ/mol
= 1223 kJ/mol
From the given energies, total energy used in the formation of bonds is:
C-C bond = 347 kJ/mol
4 C-Br bonds = 4 * 276 kJ/mol
= 1104 kJ/mol
Total energy for formation of bond = 347 kJ/mol + 1104 kJ/mol
= 1451 kJ/mol
[tex]\rm \Delta H^0_r_x[/tex] for reaction = Energy for formation of bonds - Energy released for breaking of bonds
[tex]\rm \Delta H^0_r_x[/tex] = 1451 kJ/mol - 1223 kJ/mol
= 228 kJ/mol
Since there is release of energy, minus sign is imparted.
So energy released in the given reaction is -228 kJ/mol.
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