Respuesta :
Answer:
a) 0.04
b) 0.19
c) 0.01
d) 0.8
Step-by-step explanation:
Hi,
Let's make our data, considering two rules of probability:
- The total probability of any event is 1.
- Percentages are converted to decimal.
- P(M) = 0.95
- P(M')=0.05
- P(B)=0.80
- P(B')=0.20
- where M → Main Engine works, B → Back Up Engine works, M' → Main Engine will not work and B' → Back Up Engine will not work.
Remember for cases with and, we multiply; for cases with or, we use addition.
a) For this part, we know that Main Engine will work and Back-up engine will not work:
P(M' and B): 0.05 x 0.80 = 0.04
b) Back up will not work and Main will work:
P(M and B') = 0.20 x 0.95 = 0.19
c) We know the probability of entire component working, which is 0.99.
So to find the probability of entire component failing, we need to subtract 0.99 from 1. (Since the total probability is always 1)
P(Entire component will fail) = 1 - 0.99 = 0.01
d) This is a typical case of conditional probability, to calculate a conditional probability we use the following formula: [tex]P(A|B) = \frac{P(A\ and\ B)}{P(B)}[/tex]
Where, [tex]P(A|B)[/tex] means the probability of A, given B.
Simply using this, we calculate the [tex]P(B|M')[/tex]:
[tex]P( B\ and\ M') = 0.04[/tex] (as calculated in part a)
[tex]P(M')=0.05[/tex] (as calculated for the data)
Modifying the formula to our needs: [tex]P(B|M') = \frac{P(B\ and\ M')}{P(M')}[/tex]
⇒[tex]P(B|M') = \frac{0.04}{0.05} = 0.80[/tex] Ans.
I hope this answers all your queries.