A spherical balloon is being inflated so that its diameter is increasing at a rate of 2 cm/min. How quickly is the volume of the balloon increasing when the diameter is 10 cm?

Respuesta :

Answer:

1/50π cm/min

Step-by-step explanation:

The rate of change of the sphere is 2cm/min

dv/dt = 2cm/min

The volume of a sphere is given by

V= 4/3 πr^3

Since the diamter is 10cm, then the radius is 5cm

Therefore

Dv/dt = dr/dv * dv/dt

To find Dr/dv we differentiate

V= 4/3 πr^3 which will give 4πr^2

2 = 4πr^2* dv/Dr

2/4πr^2 = dv/dt

Dv/dt = 2/ 4×5×5π

Dv/dt= 1/50π

The volume is increasing at the rate of 1/50π

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