Question

Astrology, that unlikely and vague pseudoscience, makes much of the position of the planets at the moment of one's birth. The only known force a planet exerts on Earth is gravitational.Calculate the magnitude of the gravitational force exerted on 4.2 kg baby by a 100 kg father 0.2 m away at birth.

Answer 1

Answer:

$7.01*10^{-8}$N

Explanation:

Gravitational force formula is given by;

$F_{g}=\frac{GMm}{(r)^{2}}$

where G = gravitational constant

M and m = masses given

r = distance given in radius

Concerning this question, we can make a substitute of the formula to be:

$F_{father}=\frac{G*M_{father}*m_{baby}}{(r)^{2}}$

Where; G = gravitational constant ⇒  $6.673*10^{-11}\frac{Nm^2}{kg^2}$

M = mass of the father ⇒ 100kg

m = mass of the child ⇒ 4.2kg

r = distance between father and child ⇒ 0.2m

$F_{father}$ = $\frac{6.673*10^{-11}\frac{Nm^2}{kg^2} *100kg*4.2kg}{(0.2m)^2}$

                                = $7.01*10^{-8}$N

∴ We can now conclude that the gravitational force exerted on the baby by the father at birth is $7.01*10^{-8}$N