Answer:
[tex]A=47.25\ in^2[/tex]
Step-by-step explanation:
The picture of the question in the attached figure
we know that
The area of a trapezoid is equal to
[tex]A=\frac{1}{2}[b_1+b_2]h[/tex]
where
b_1 and b_2 are the parallel bases
h is the perpendicular distance between the parallel bases
we have
[tex]b_1=4.5\ in\\b_2=9\ in\\h=7\ in[/tex]
substitute
[tex]A=\frac{1}{2}[4.5+9]7[/tex]
[tex]A=47.25\ in^2[/tex]