Question

Estimate the frequency of vibration of your arm.
Let the length of the arm be 0.59 m. Consider the arm as a simple pendulum and assume its center of mass is about 2/3 its length from the shoulder.

Answer 1

Answer:

0.7945 Hz

Explanation:

Data provided in the question:

Length of the arm = 0.59 m

Since the center of mass lies at about $\frac{2}{3}$ of its length

Thus,

Length of the simple pendulum = $\frac{2}{3}$ × 0.59 m = 0.3933 m

Now,

Frequency of vibration, f = $\frac{1}{2\pi}\sqrt\frac{g}{l}$

Thus,

we have,

Frequency of vibration for the arm = $\frac{1}{2\pi}\sqrt\frac{9.8}{0.3933}$

or

Frequency of vibration for the arm = 0.7945 Hz

Answer 2

Answer: 0.7945

Explanation: