Answer:
0.13591.
Step-by-step explanation:
We re asked to find the probability of randomly selecting a score between 1 and 2 standard deviations below the mean.
We know that z-score tells us that a data point is how many standard deviation above or below mean.
To solve our given problem, we need to find area between z-score of -2 and -1 that is [tex]P(-2<z<-1)[/tex].
We will use formula [tex]P(a<z<b)=P(z<b)-P(z<a)[/tex] to solve our given problem.
[tex]P(-2<z<-1)=P(z<-2)-P(z<-1)[/tex]
Using normal distribution table, we will get:
[tex]P(-2<z<-1)=0.15866-0.02275[/tex]
[tex]P(-2<z<-1)=0.13591[/tex]
Therefore, the probability of randomly selecting a score between 1 and 2 standard deviations below the mean would be 0.13591.
