PLEASE MARK BRAINLIEST!
Answer:
To solve, you must split the figure into 2 parts --> a rectangle and a trapezoid. The separating 'line' will be where the figure indents and starts to jut out. That separating 'line' will be 9 cm long.
Area of the rectangle:
A = bh
A = 9(15)
A = 135
The area of the rectangle is 135 cm².
Area of the trapezoid:
A = [tex]\frac{a + b}{2}h[/tex]
A = [tex]\frac{9+18}{2}12[/tex]
A = [tex]\frac{27}{2}12[/tex]
A = [tex]\frac{13.5}{1}12[/tex]
A = [tex]13.5(12)[/tex]
A = [tex]162[/tex]
The area of the trapezoid is 162 cm².
Area of the figure:
To find the area of the figure, you must add the area of the rectangle and the area of the trapezoid together.
A = 135 cm² + 162 cm²
A = 297 cm²
So your answer is --> C) 297 cm²
I hope this helps!
- sincerelynini
