Question

What is the molarity (M) of the following solutions?

a. 19.2 g of Al(OH)3 dissolved in water to make 280 mL of solution

b. A 2.6 L solution made with 235.9 g of KBr​

Answer 1

Answer:

Explanation:

Al 27g/m  3(OH) = 3x17= 51  51+27=78g/m Al(OH)3

19.2g/78g/m = 0.25m

0.25m/280mL= 0.25 m/0.280 L= .88m/L

K= 39g/m  Br = 80 g/m  KBr = 119 g/m

235.9 g/119g/m = 1.98 moles

1.98 mole/2.6L = 0.76 m/L = 0.76 molar