Question

If 3 g of sodium reacts with chlorine, how many grams of sodium chloride will be
produced?

Answer 1

Answer:

                      7.63 g of NaCl

Explanation:

                   The balance chemical equation for given neutralization reaction is,

                                          2 Na + Cl₂ → 2 NaCl

Step 1: Calculate Moles of Na as;

             Moles = Mass / A. Mass

             Moles = 3.0 g / 22.98 g/mol

             Moles = 0.130 mol

Step 2: Find out moles of NaCl produced as;

According to equation,

                     2 moles of Na produced  =  2 moles of NaCl

So,

               0.130 moles of Na will produce  =  X moles of NaCl,

Solving for X,

                     X =  2 mol × 0.130 mol / 2 mol

                      X =  0.130 moles of NaCl

Step 3: Calculating Mass of NaCl as;

             Mass = Moles × M.Mass

             Mass = 0.130 mol × 58.44 g/mol

             Mass  = 7.63 g of NaCl