Answer:
58425.84 kJ is released when 4.337 pounds of liquid ethanol are burned.
Explanation:
Given that:-
When 1 gram of liquid ethanol is burnt, 29.7 kJ of energy is released.
The conversion of pounds to gram is shown below as:-
1 pound = 453.6 gram
Given mass of liquid ethanol = 4.337 pounds.
So,
4.337 pounds = 453.6*4.337 grams = 1967.2 grams
Thus,
When 1967.2 gram of liquid ethanol is burnt, 29.7*1967.2 kJ of energy is released.
58425.84 kJ is released when 4.337 pounds of liquid ethanol are burned.