Respuesta :

Answer:

T' [tex](\frac{5}{13},- \frac{12}{13})[/tex]

Step-by-step explanation:

See the diagram attached.

This is a unit circle having a radius (r) = 1 unit.

So, the length of the circumference of the circle will be 2πr = 2π units.

Now, the point on the circle at a distance of x along the arc from P is T[tex](\frac{5}{13},\frac{12}{13})[/tex].

Therefore, the point on the circle at a distance of 2π - x along the arc from P will be T' [tex](\frac{5}{13},- \frac{12}{13})[/tex], where, T' is the image of point T, when reflected over the x-axis. (Answer)

ACCESS MORE