Answer:
Step-by-step explanation:
he perimeter of a rectangular parking lot is 146 yards what is the dimensions
if the length is 7 yards less than 4 times the width
Let x represent the width and (4x-7)the length
Question states***
146 = 2(4x-7) + 2x
Solving for x
10x = 160
x = 16 yd, the width and the length is 57 yds
CHECKING our Answer***
114yd + 32yd = 146yd
