Answer:
The value of s in the given equation is [tex]\frac{a(1-r^5)}{1-r}[/tex]
Therefore [tex]s=\frac{a(1-r^5)}{1-r}[/tex]
Step-by-step explanation:
Given equation is [tex]s-rs=a-ar^5[/tex]
To find the value of s :
[tex]s-rs=a-ar^5[/tex]
Taking common term "s" outside in LHS and common term "a" outside in RHS
[tex]s(1-r)=a(1-r^5)[/tex]
Dividing by (1-r) on both sides we get
[tex]\frac{s(1-r)}{1-r}=\frac{a(1-r^5)}{1-r}[/tex]
[tex]s=\frac{a(1-r^5)}{1-r}[/tex]
Therefore the value of s in the given equation is [tex]\frac{a(1-r^5)}{1-r}[/tex]
Therefore [tex]s=\frac{a(1-r^5)}{1-r}[/tex]